[MV] Re: Vehicle gradability, degrees vs. per cent

Andreas Mehlhorn (a.mehlhorn@t-online.de)
Tue, 17 Mar 1998 19:12:28 +0100

Dr Deuce 264-0909 schrieb:
> I am not sure.
>
> If 90 degrees is straight up, then 65 degrees would be pretty steep, but =
not
> impossible.
>
> How did you come up with 214 % ?

If you name the gradient in per cent, this means the ratio between
"going up" and "going forward". In Germany gradients on roads are
signposted in per cent. In England they signposte the gradient's=20
ratio like "1 : 9" or so. (Before the EU regulations came...)=20

0 per cent means you only go forward. (Angle 0 degrees)
Going straight up (90 degrees) is not 100 per cent, this is infinite
per cent (devide by zero error).

100 per cent means, you go 1 metre (foot, mile, what ever you want) up
and at the same time 1 metre (foot, mile, what ever you want) forward.
This is at an angle of 45 degrees. The English would write "1 : 1"

At 65 degrees, you go 2.14 metres up, when you go 1 metre forward. No
tracked or wheeled vehicle can do that. You do it when you climb a=20
ladder.

Vehicles can climb 65 per cent grades (English: "1 : 1.54") or if
you want it in degrees: 33 degrees.

In the driver's manual of my Kettenkrad is written, that the Kettenkrad
can climb a grade of 24 degrees (44 per cent or "1 : 2.3") at combat
weight on loose sand. With trailer half of this.

Take a ruler and paint an angle of 65 degrees on a piece of paper.
You'll see immediatelly that this can't climb any vehicle.

Regards
Andreas

=20
=20

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